Rút gọn biểu thức \(S\left(x\right)=\dfrac{1}{x^2}+\dfrac{2}{x^3}+\dfrac{3}{x^4}+...+\dfrac{n}{x^{n+1}}\) bằng:

A. \(S=\dfrac{x^{n+1}-\left(n+1\right)x+n}{x^{n+1}\left(x-1\right)^2}\)

B. \(S=\dfrac{x^{n+1}-\left(n+1\right)x+n}{x^{2n}\left(x-1\right)^2}\)

C. \(S=\dfrac{x^n-\left(n+1\right)x+n}{x^n\left(x-1\right)^2}\)

D. \(S=\dfrac{x^{n+1}-\left(n+1\right)x+n}{x^n\left(x-1\right)^2}\)

Rút gọn biểu thức \(S\left(x\right)=\dfrac{1}{x^2}+\dfrac{2}{x^3}+\dfrac{3}{x^4}+...+\dfrac{n}{x^{n+1}}\) bằng:

A. \(S=\dfrac{x^{n+1}-\left(n+1\right)x+n}{x^{n+1}\left(x-1\right)^2}\)

B. \(S=\dfrac{x^{n+1}-\left(n+1\right)x+n}{x^{2n}\left(x-1\right)^2}\)

C. \(S=\dfrac{x^n-\left(n+1\right)x+n}{x^n\left(x-1\right)^2}\)

D. \(S=\dfrac{x^{n+1}-\left(n+1\right)x+n}{x^n\left(x-1\right)^2}\)

Bài 1 : Rút gọn biểu thức                                                                                  

a. A = \(\left(a-2\right):\left\{\dfrac{a^2-b^2}{a^3+b^3}.\left[a-\dfrac{a^2+b^2}{b}:\left(\dfrac{1}{a}-\dfrac{1}{b}\right)\right]\right\}=\dfrac{a-2}{a}\)        

b. B = \(1:\left(\dfrac{x+2}{x\sqrt{x}-1}+\dfrac{\sqrt{x}+1}{x+\sqrt{x}+1}-\dfrac{\sqrt{x}+1}{x-1}\right)\)     

2. Chứng minh đẳng thức :

a. \(\left(\dfrac{6a+1}{a^2-6a}+\dfrac{6a-1}{a^2+6a}\right).\dfrac{a^2-36}{a^2+1}=\dfrac{12}{a}\)

b.  \(\dfrac{\sqrt{x}-\sqrt{y}}{xy\sqrt{xy}}:\left[\left(\dfrac{1}{x}+\dfrac{1}{y}\right).\dfrac{1}{x+y+2\sqrt{xy}}+\dfrac{2}{\left(\sqrt{x}+\sqrt{y}\right)^3}.\left(\dfrac{1}{\sqrt{x}}+\dfrac{1}{\sqrt{y}}\right)\right]=\dfrac{\sqrt{x}-\sqrt{y}}{\sqrt{xy}}\)

Bài 1 : Rút gọn biểu thức                                                                                  

a. A = \(\left(a-2\right):\left\{\dfrac{a^2-b^2}{a^3+b^3}.\left[a-\dfrac{a^2+b^2}{b}:\left(\dfrac{1}{a}-\dfrac{1}{b}\right)\right]\right\}=\dfrac{a-2}{a}\)        

b. B = \(1:\left(\dfrac{x+2}{x\sqrt{x}-1}+\dfrac{\sqrt{x}+1}{x+\sqrt{x}+1}-\dfrac{\sqrt{x}+1}{x-1}\right)\)     

2. Chứng minh đẳng thức :

a. \(\left(\dfrac{6a+1}{a^2-6a}+\dfrac{6a-1}{a^2+6a}\right).\dfrac{a^2-36}{a^2+1}=\dfrac{12}{a}\)

b.  \(\dfrac{\sqrt{x}-\sqrt{y}}{xy\sqrt{xy}}:\left[\left(\dfrac{1}{x}+\dfrac{1}{y}\right).\dfrac{1}{x+y+2\sqrt{xy}}+\dfrac{2}{\left(\sqrt{x}+\sqrt{y}\right)^3}.\left(\dfrac{1}{\sqrt{x}}+\dfrac{1}{\sqrt{y}}\right)\right]=\dfrac{\sqrt{x}-\sqrt{y}}{\sqrt{xy}}\)

3. Chứng minh biểu thức không phụ thuộc vào biến :

a. A = \(\left(\dfrac{x}{x-y}-\dfrac{y}{x+y}\right):\left(\dfrac{x+y}{x-y}-\dfrac{2xy}{x^2-y^2}\right)\)

b. \(\left(\dfrac{1-a\sqrt{a}}{1-\sqrt{a}}+\sqrt{a}\right)\left(\dfrac{1-\sqrt{a}}{1-a}\right)^2\)

Bài 1 : Rút gọn biểu thức                                                                                  

a. A = \(\left(a-2\right):\left\{\dfrac{a^2-b^2}{a^3+b^3}.\left[a-\dfrac{a^2+b^2}{b}:\left(\dfrac{1}{a}-\dfrac{1}{b}\right)\right]\right\}=\dfrac{a-2}{a}\)        

b. B = \(1:\left(\dfrac{x+2}{x\sqrt{x}-1}+\dfrac{\sqrt{x}+1}{x+\sqrt{x}+1}-\dfrac{\sqrt{x}+1}{x-1}\right)\)     

2. Chứng minh đẳng thức :

a. \(\left(\dfrac{6a+1}{a^2-6a}+\dfrac{6a-1}{a^2+6a}\right).\dfrac{a^2-36}{a^2+1}=\dfrac{12}{a}\)

b.  \(\dfrac{\sqrt{x}-\sqrt{y}}{xy\sqrt{xy}}:\left[\left(\dfrac{1}{x}+\dfrac{1}{y}\right).\dfrac{1}{x+y+2\sqrt{xy}}+\dfrac{2}{\left(\sqrt{x}+\sqrt{y}\right)^3}.\left(\dfrac{1}{\sqrt{x}}+\dfrac{1}{\sqrt{y}}\right)\right]=\dfrac{\sqrt{x}-\sqrt{y}}{\sqrt{xy}}\)

3. Chứng minh biểu thức không phụ thuộc vào biến :

a. A = \(\left(\dfrac{x}{x-y}-\dfrac{y}{x+y}\right):\left(\dfrac{x+y}{x-y}-\dfrac{2xy}{x^2-y^2}\right)\)

b. \(\left(\dfrac{1-a\sqrt{a}}{1-\sqrt{a}}+\sqrt{a}\right)\left(\dfrac{1-\sqrt{a}}{1-a}\right)^2\)